SOLUTION: 8-2(x-3)<4(x-10)+8
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Question 218773: 8-2(x-3)<4(x-10)+8
Found 2 solutions by drj, MathTherapy:
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
Step 1. Multiply to get rid of parenthesis
Step 2. Add x+32 to both sides of inequality
Step 3. Divide 4 to both sides of the inequality
Step 4. ANSWER
I hope the above steps were helpful.
For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
And good luck in your studies!
Respectfully,
Dr J
http://www.FreedomUniversity.TV
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
8 - 2(x - 3) < 4(x - 10) + 8
8 - 2x + 6 < 4x - 40 + 8 ----- Distribute to get rid of the parentheses
- 2x + 14 < 4x - 32
- 2x - 4x < - 32 - 14
- 6x < - 46
x > , or x > , or, x > . You should have realized that the < changes to > because of the divsion by a negative number
------------
Let's check
------------
Since x > 7.667, let's make x = 8
We then have:
8 - 2(x - 3) < 4(x - 10) + 8
8 - 2(8 - 3) < 4(8 - 10) + 8
8 - 2(5) < 4(- 2) + 8
8 - 10 < - 8 + 8
- 2 < 0 (TRUE)
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