SOLUTION: If a baseball is projected upward from the ground level with an initial velocity of 64 feet per second, then its height is a function of time, geven by s(t) = - 16t^2 + 64t. Graph

Algebra ->  Inequalities -> SOLUTION: If a baseball is projected upward from the ground level with an initial velocity of 64 feet per second, then its height is a function of time, geven by s(t) = - 16t^2 + 64t. Graph       Log On


   

Question 21207: If a baseball is projected upward from the ground level with an initial velocity of 64 feet per second, then its height is a function of time, geven by s(t) = - 16t^2 + 64t. Graph this function for 0 < t < 4. what is the maximum height reached by the ball?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case -64x%5E2%2B64x%2B0+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%2864%29%5E2-4%2A-64%2A0=4096.

Discriminant d=4096 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-64%2B-sqrt%28+4096+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%2864%29%2Bsqrt%28+4096+%29%29%2F2%5C-64+=+0
x%5B2%5D+=+%28-%2864%29-sqrt%28+4096+%29%29%2F2%5C-64+=+1

Quadratic expression -64x%5E2%2B64x%2B0 can be factored:
-64x%5E2%2B64x%2B0+=+%28x-0%29%2A%28x-1%29
Again, the answer is: 0, 1. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-64%2Ax%5E2%2B64%2Ax%2B0+%29


Cheers,
Stan H.