|3.5z| > |7|

The absolute value of 7 is just 7, so the right side
is just 7

|3.5z| > 7

Since 3.5 is positive, we may write
the left side as

3.5|z| > 7

Divide both sides by 3.5





|z| > 2

So the distance any number which variable z can take 
on must be more than 2 units from 0, on either side
of 0, so the graph of the inequality on a number line is:

<================o-----------o===============>
 -7 -6 -5 -4 -3 -2 -1  0  1  2  3  4  5  6  7 

In interval notation the solution set is written:

          

In set-builder notation the solution set is written

         {z|z<-2 OR z>2}

Edwin