SOLUTION: Word Problem:
Find the lesser of two consecutive integers whose sum is greater than 16.
Algebra.Com
Question 209139: Word Problem:
Find the lesser of two consecutive integers whose sum is greater than 16.
Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the lesser of two consecutive integers whose sum is greater than 16.
--------
x + x+1>16
2x + 1>16
2x > 15
x>7.5, but since it's an integer
x>8
----
It can be any 2 integers greater than 8, 8 & 9, 22 & 23, 12345 & 12346.
It didn't ask for the least, it asked for "the lesser."
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Find the lesser of two consecutive integers whose sum is greater than 16.
Let the lesser integer be I
Then the larger integer is: I + 1
Since the sum of both is greater than 16, then:
I + I + 1 > 16
2I > 15
=
Any number greater than can be used as the lesser of the two numbers, as long as 1 is added to the lesser chosen number to get the larger number.
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