SOLUTION: 2x^2+4x>15

Algebra.Com
Question 202220: 2x^2+4x>15
Answer by RAY100(1637)   (Show Source): You can put this solution on YOUR website!
Just solve as equality then check inequalities
.
2x^2 +4x >15
.
2x^2 +4x-15=0
.
using quadratic formula
.
x=1.91,,,,x=-3.915
.
on a number line this makes three areas
.
x<-3.915,,,,test point (-4),,,checking inequality,,2(-4)^2 +4(-4) >15,,,32-16>15,,16>15,,,ok
.
-3.91515,,,,not true
,
x>1.91,,,,test point (+3),,,2(3)^2+4(3)>15,,18+12>15,,30>15 ,,,ok
.
Therefore,,x>1.91,,,x<-3.915

RELATED QUESTIONS

2x-y=5 and... (answered by ikleyn)
simplify fully... (answered by Alan3354)
Multiply... (answered by london maths tutor)
2X+15=27+4X (answered by rfer)
2x+15=27-4x (answered by stanbon)
Simplify 4x^2+20x+25 over 4x^2-25 divided 1 over... (answered by Fombitz)
Simplify. If possible work must me shown.... (answered by Edwin McCravy)
Divide. x^2+2x-15/4x^2 / x^2-25/2x-10 Thank... (answered by Cintchr,sdmmadam@yahoo.com)
x^2 + 2x - 15/4x^2 divided by x^2 - 25/2x -... (answered by gsmani_iyer)