SOLUTION: I am supposed to solvr this and then graph but I have no clue what to do. Please help. 6y+2y<-16 This symbol< has the equal to line under it but I could not find how to do it o

Algebra ->  Algebra  -> Inequalities -> SOLUTION: I am supposed to solvr this and then graph but I have no clue what to do. Please help. 6y+2y<-16 This symbol< has the equal to line under it but I could not find how to do it o      Log On

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Question 200031: I am supposed to solvr this and then graph but I have no clue what to do. Please help.
6y+2y<-16 This symbol< has the equal to line under it but I could not find how to do it on my keyboard.
I have to put it like this {y/y ? ? }

Found 2 solutions by RAY100, jim_thompson5910:
Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
If problem is really, 6y +2y < or = -16
.
8y < or = -16
.
y< or = -2
.
Graph is a solid horizontal line at y= -2, area of concern is below line( crosshatch)
.
.
IF however, the problem is,,6x +2y <= -16
.
Calc points in T Box
.
X,,,,,,,,Y
0,,,,,,,,-8
-2.67,,,,0
.
Plot a solid line thru these points
.
To define the area of concern , use a test point (0,0) on eqn,,,0,<= -16,, not true therefore
area of concern is on other side of line, that is to the left of line, (crosshatch)

Answer by jim_thompson5910(21682) About Me  (Show Source):
You can put this solution on YOUR website!
6y%2B2y%3C=-16 Start with the given inequality.


8y%3C=-16 Combine like terms on the left side.


y%3C=%28-16%29%2F%288%29 Divide both sides by 8 to isolate y.


y%3C=-2 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is y%3C=-2



So the answer in set-builder notation is


Here's the graph of the solution set

drawing%28500%2C80%2C-12%2C+8%2C-10%2C+10%2C%0D%0Anumber_line%28+500%2C+-12%2C+8%29%2C%0D%0A%0D%0A%0D%0Aarrow%28-2%2C0%2C-12%2C0%29%2C%0D%0Aarrow%28-2%2C0.30%2C-12%2C0.30%29%2C%0D%0Aarrow%28-2%2C0.15%2C-12%2C0.15%29%2C%0D%0Aarrow%28-2%2C-0.15%2C-12%2C-0.15%29%2C%0D%0Aarrow%28-2%2C-0.30%2C-12%2C-0.30%29%2C%0D%0A%0D%0A%0D%0A%0D%0A%0D%0Acircle%28-2%2C0%2C0.2%29%2C%0D%0Acircle%28-2%2C0%2C0.15%29%2C%0D%0Acircle%28-2%2C0%2C0.1%29%2C%0D%0Acircle%28-2%2C0%2C0.2-0.02%29%0D%0A%29

Take note that there is an CLOSED circle at the endpoint.