SOLUTION: y>x-2
3x+y>2
Algebra.Com
Question 198514: y>x-2
3x+y>2
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Usually use graphics to solve inequalities. Let's use a rough sketch
.
y> x-2,,,,,,,has T box,,,,X,,,,,,,,,Y
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,0,,,,,,,,,-2
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,2,,,,,,,,,0
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,1,,,,,,,,,-1
test point (0,0),,0>-2, ok,,,use this side
.
3x+y >2,,,,,has a T Box,,,,X,,,,,,,,Y
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, 0,,,,,,,2
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,2/3,,,0
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,1,,,,,-1
Test point (0,0) 0>2, no,, use other side
.
Now, draw a rough sketch, dotted lines only, as full inequality
.
Intersection is at (1,-1)
.
Area of concern is above positive line, and to right of negative line.
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