SOLUTION: In 1978 Udo Beyer (East Germany) set a world record in the shot-put of 72 ft 8 in. If Beyer had projected the shot straight upward with a velocity of 30 ft/sec from a height of 5 f
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Question 189576This question is from textbook Elementary and Intermediate Algebra
: In 1978 Udo Beyer (East Germany) set a world record in the shot-put of 72 ft 8 in. If Beyer had projected the shot straight upward with a velocity of 30 ft/sec from a height of 5 ft, then for what values of t would the shot be under 15 ft high?
This question is from textbook Elementary and Intermediate Algebra
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
In 1978 Udo Beyer (East Germany) set a world record in the shot-put of 72 ft 8 in. If Beyer had projected the shot straight upward with a velocity of 30 ft/sec from a height of 5 ft, then for what values of t would the shot be under 15 ft high?
:
Gravity: -16t^2, upward velocity 30t, initial height: 5'; gives us an equation of:
:
h = -16t^2 + 30t + 5
:
" for what values of t would the shot be under 15 ft high?"
-16t^2 + 30t + 5 < 15
:
-16t^2 + 30t + 5 - 15 = 0
:
-16t^2 + 30t - 10 = 0
Solve this using the quadratic formula: a=-16; b=30; c=-10
:
You should get two solutions
t ~ .43 sec
t ~ 1.44 sec
:
We can say that shot-put was below 15 ft from 0 to .43 sec
and it was below 15 ft from 1.44 sec until it hit the ground
Find out when it hit the ground (h=0) using the equation
-16t^2 + 30t + 5 = 0
;
Use a graph for this, green line represents 15 ft; time (t) on the x axis:
It was below 15 ft from 1.44 sec to approx 2 sec when it hit the ground
:
:
did this make sense to you?
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