SOLUTION: I have to solve by graphing. I have attempted this problem but i am not certian that i did it correctly. It is 2x-3y>=-3 and 3y>-2x-6. the point of intersection i came up with wa

Algebra ->  Inequalities -> SOLUTION: I have to solve by graphing. I have attempted this problem but i am not certian that i did it correctly. It is 2x-3y>=-3 and 3y>-2x-6. the point of intersection i came up with wa      Log On


   

Question 175332: I have to solve by graphing. I have attempted this problem but i am not certian that i did it correctly. It is 2x-3y>=-3 and 3y>-2x-6. the point of intersection i came up with was around (-2.5, .5). If this is incorrect could you please explain why and the correct way to do it? thanks!
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Solve by graphing
2x-3y>=-3 and 3y>-2x-6:
;
We need these equations in the general y= form to plot the graphs.
1st equation:
2x - 3y >= -3
-3y >= -2x - 3
y has to be positive, multiply equation by -1, then we have to reverse the inequality sign
3y <= 2x + 3
Divide equation by 3 and we have
y <= 2%2F3x + 1; purple line
;
2nd equation:
3y > -2x - 6
Divide equation by 3 and we have:
y > -2%2F3x - 2; green line
:
Plot both these equations: find y for x=-3 and x=+3
Should look like this
+graph%28+300%2C+200%2C+-6%2C+4%2C+-5%2C+3%2C+.6667x%2B1%2C+-.6667x-2%29+
:
The solution area is above (>) the green line and at or below (=<) the purple line
:
The point of intersection is close to what you said. I get -2.25, -.5, but I
think they are asking for the solution area or "area of feasibility" when
they say solve inequalities like this.