SOLUTION: how do you solve this quadratic equation.y >/= x^2-3x+1

Question 1658: how do you solve this quadratic equation.y >/= x^2-3x+1
Found 2 solutions by AnlytcPhil, smartdude17:
Answer by AnlytcPhil(1810) (Show Source): You can put this solution on YOUR website!

How do you graph the solution set for this quadratic inequality?:
`
y > x² - 3x + 1
`
You first graph the equation of the boundary equation, which is
found by replacing the inequality " > " by an equal sign
" = ": Since the inequality is " > " rather than " > " we draw
the graph with a solid line.
`
[When the inequality sign is " > " or " < ",
we draw the graph solid since it includes the boundary line,
and when the inequality is " > " or " < " we draw it dashed or
dotted].
`
So we wish to graph the boundary y = x² - 3x + 1
`
Make a table of points:
`
` x | y ` `|` `point` `|
` ----------------------
`-1 | 5 ` `|` (-1,5) ` |
` 0 | 1 ` `|` `(0,1) ` |
` 1 |-1 ` `|``(1,-1)` `|
1.5 |-1.25 |(1.5,-1.25)|
` 2 |-1 ` `|` (2,-1)` `|
` 3 |`1 ` `|` `(3,1)` `|
` 4 |`5 ` `|` `(4,5)` `|
`
Plot these points and you get this graph
`

`
Now the rules for shading, which I can't do here, but which
you can do on your paper are:
`
If the inequality is " > " or " > ", then shade the area
ABOVE the boundary graph.
`
If the inequality is " < " or " < " then shade the area
BELOW the boundary graph.
`
So since the inequality is " > " you are to shade the area
ABOVE (inside) the boundary graph drawn above.
`
Edwin J
Answer by smartdude17(30) (Show Source): You can put this solution on YOUR website!
Very simple. I will show you:
y >/= x^2-3x+1 G
0=x^2-3x+1 lety=0,let sign be=
QF
Sub,S
And this is your answer. It is in the radical form. There is no sqrt of five besides 2.24. And besides, this is the scantron answer. Good Luck in all of your other problems!
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