SOLUTION: Solve: x-3/3>=0 I got: 0> x >=3 Any clue if this is possibly close to being right? I am assuming x-3 is above the 3 or .... (x-3)/3 >= 0 3((x-3)/3) >= 0(3) x-3 >= 0

Question 162915This question is from textbook
: Solve: x-3/3>=0
I got: 0> x >=3
Any clue if this is possibly close to being right?
I am assuming x-3 is above the 3 or ....
(x-3)/3 >= 0
3((x-3)/3) >= 0(3)
x-3 >= 0
x-3+3 >= 0+3
x >= 3
Check:
(3-3)/3 =0 which is >= 0
(4-3)/3=1/3 which is >=0
answer is correct

Case 2: Assuming
x- (3/3) >=0
x-1 >=0
x-1+1 >= 0+1
x >= 1

This question is from textbook

Answer by eperette(173) (Show Source): You can put this solution on YOUR website!

RELATED QUESTIONS
This is multiplying binomials mentally, my problem is (x+5)(x+2), when I solved it, I got (answered by vleith)

log(7)x=5 the answer I got is x=16,954 and also log x =1 the answer I got is x=10 (answered by Theo)

Solve each equation -3/x = x/-3 I think it is -3x(-3/x) = -3x(x/-3) 9 = x^2 0 = x^2 (answered by Fombitz)

plese help me anwer this question i willput down the answer i originally recived but need (answered by Alan3354)

Hello I am working with the Descartes rule of signs. I am supposed to discuss the... (answered by stanbon)

How do i solve this 2x^0 . 4y --------- x^3 (answered by stanbon)

I am reviewing for a test and I think I got the first 3 right. Can anybody check my... (answered by Alan3354)

Hi any help would be appreatiated my question is : What is the slope and y-intercept of... (answered by richard1234)