SOLUTION: 10 < x < 20 and 40 < y < 60, find the largest value of x^/2y

Question 159559: 10 < x < 20 and 40 < y < 60, find the largest value of x^/2y

Found 2 solutions by Fombitz, jim_thompson5910:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Please check your formula and re-post.
x^/2y
Do you mean ???
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Note: I'm assuming that "x" and "y" are integers

If you meant to post , then the largest value of will have the largest possible (or the largest possible x). So this means that (if x is an integer). Also the largest value of will have the smallest possible "y" value. So this means that

So when and , this means that which is the largest value when 10 < x < 20 and 40 < y < 60
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