SOLUTION: I've been having some trouble solving this particular problem, mainly because I don't know how to turn it into an equation. Can someone please help me? Many thanks in advance.

Question 149901This question is from textbook Algebra and Trigonometry: Structure and Method - Book 2
: I've been having some trouble solving this particular problem, mainly because I don't know how to turn it into an equation. Can someone please help me? Many thanks in advance.

"12. During the first 20 mi of a 50 mi bicycle race, Roger's average speed was 16 mi/h. What must his average speed be during the remainder of the race if he is to finish in less than 2.5 hours?" This question is from textbook Algebra and Trigonometry: Structure and Method - Book 2

Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
During the first 20 mi of a 50 mi bicycle race, Roger's average speed was 16 mi/h. What must his average speed be during the remainder of the race if he is to finish in less than 2.5 hours?
.
The time Roger takes to finish the first 20 miles of the race is:
20/16 hours
or
1 and 1/4 hours
.
If he wants to finish the race in less than 2.5 hours he must travel the rest of the race (30 miles) in less than this amount of time:
2.5 - 1.25 = 1.25 hours
.
Therefore, his speed must be "greater than":
30/1.25 = 24 mph
.
solution: >24 mph
(that is, "greater than" 24 mph)
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