SOLUTION: solve the inequality 2x+6>x-4 solve the inequality 3x+2< (or equal to)-16 solve the inequality 6-3x< (or equal to) 18 solve the inequality -8<2(x-3)< (or equal to) 8 Ca

Algebra.Com
Question 143635: solve the inequality 2x+6>x-4
solve the inequality 3x+2< (or equal to)-16
solve the inequality 6-3x< (or equal to) 18
solve the inequality -8<2(x-3)< (or equal to) 8
Can someone PLEASE exmplain these problems to me.
It has been 20+ years since I have taken math and all this looks Greek to me.
Any help you can give would be appreciated!!!
Thank you!!!!

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
I'll do the first two to get you started


# 1



Start with the given inequality



Subtract 6 from both sides


Subtract x from both sides


Combine like terms on the left side


Combine like terms on the right side

--------------------------------------------------------------
Answer:
So our answer is









# 2




Start with the given inequality



Subtract 2 from both sides


Combine like terms on the right side


Divide both sides by 3 to isolate x



Divide

--------------------------------------------------------------
Answer:
So our answer is




RELATED QUESTIONS

Solve the inequality (3x+2)/((x+1)(2x))< or equal to... (answered by rothauserc)
solve the compound inequality 4>-3x+3 or 6<-3x+2 the symbol< should be less than are... (answered by stanbon)
solve the inequality {x}-9 equal or more to... (answered by lynnlo)
Solve the following inequality: -2x^(2/3)>(or equal... (answered by stanbon,lwsshak3)
how do you solve the inequality 1/3x is greater than or equal to... (answered by Alan3354)
Solve for the rational inequality and find the interval. ((3x-3) /(4-2x)) is more than... (answered by stanbon)
Solve the compound inequality. 0 < 6 -2x is less or equal to 10. (answered by Earlsdon)
Solve each inequality. Express the solution set on a number line. a) 8-3x is greater... (answered by nyc_function)
solve the inequality, -x^2+2x (< or equal to) -6x+12 (answered by lynnlo)