You can
put this solution on YOUR website!1) A missile is fired into the air from a 100 ft hilltop such that its height above ground after ‘t’ seconds is given by the equation: h(t) = 100 + 800t – 16tsquared
a) Find the time interval for which the missile is at least 9700 ft above ground level.
-16t^2+800t+100=9700
-16t^2+800t-9600 = 0
t^2-50t+600 = 0
(t-20)(t-30)=0
t=30 ; t=30
The missile is at or above 9700 ft between 20 and 30 seconds
after launch.
------------------
b) Determine after how many seconds the missile will hit the ground.
-16t^2+800t+100=0
-4t^2+200t+25 = 0
t = (-200 +- sqrt(200^2-4*-4*25)]/-8
Positive solution:
t = (-200 - sqrt(40400)]/-8
t = 50.12 seconds
========================
Cheers,
Stan H.
(