SOLUTION: 1.On a road in the city of Rochester, the maximum speed is 50 miles per hour, and the minimum speed is 20 miles per hour. Which compound inequality represents the situation. a. 2

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Question 127769: 1.On a road in the city of Rochester, the maximum speed is 50 miles per hour, and the minimum speed is 20 miles per hour. Which compound inequality represents the situation.
a. 20>x>50
b. 20 c. 20<=x<=50
d. 20>=x>=50
2. Write an inequality for the situation:
All real numbers y that are less than 4 or greater than 9.
3. Solve the inequality:
a+8-2(a-12)>0
PLEASE HELP!!!!

Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
If the minimum speed is 20 mph, then you must go 20 mph or faster. So mathematically, this looks like . Also, if the maximum speed is 50 mph, then the upper limit is 50. So mathematically, this looks like .

So we have these two inequalities

and

Rearrange to get

Now we can combine and to get

So our answer is C

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# 2

The statement "that are less than 4" translates to and the statement "greater than 9" translates to

So together we have

or

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# 3

Start with the given inequality

Distribute

Combine like terms on the left side

Subtract 32 from both sides

Combine like terms on the right side

Divide both sides by -1 to isolate a (note: Remember, dividing both sides by a negative number flips the inequality sign)

Divide

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Answer:
So our answer is