SOLUTION: 1.On a road in the city of Rochester, the maximum speed is 50 miles per hour, and the minimum speed is 20 miles per hour. Which compound inequality represents the situation.
a. 2
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Question 127769: 1.On a road in the city of Rochester, the maximum speed is 50 miles per hour, and the minimum speed is 20 miles per hour. Which compound inequality represents the situation.
a. 20>x>50
b. 20
c. 20<=x<=50
d. 20>=x>=50
2. Write an inequality for the situation:
All real numbers y that are less than 4 or greater than 9.
3. Solve the inequality:
a+8-2(a-12)>0
PLEASE HELP!!!!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
If the minimum speed is 20 mph, then you must go 20 mph or faster. So mathematically, this looks like . Also, if the maximum speed is 50 mph, then the upper limit is 50. So mathematically, this looks like .
So we have these two inequalities
and
Rearrange to get
Now we can combine and to get
So our answer is C
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# 2
The statement "that are less than 4" translates to and the statement "greater than 9" translates to
So together we have
or
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# 3
Start with the given inequality
Distribute
Combine like terms on the left side
Subtract 32 from both sides
Combine like terms on the right side
Divide both sides by -1 to isolate a (note: Remember, dividing both sides by a negative number flips the inequality sign)
Divide
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Answer:
So our answer is
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