SOLUTION: 1.On a road in the city of Rochester, the maximum speed is 50 miles per hour, and the minimum speed is 20 miles per hour. Which compound inequality represents the situation. a. 2

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Question 127769: 1.On a road in the city of Rochester, the maximum speed is 50 miles per hour, and the minimum speed is 20 miles per hour. Which compound inequality represents the situation.
a. 20>x>50
b. 20 c. 20<=x<=50
d. 20>=x>=50
2. Write an inequality for the situation:
All real numbers y that are less than 4 or greater than 9.
3. Solve the inequality:
a+8-2(a-12)>0
PLEASE HELP!!!!

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
If the minimum speed is 20 mph, then you must go 20 mph or faster. So mathematically, this looks like . Also, if the maximum speed is 50 mph, then the upper limit is 50. So mathematically, this looks like .


So we have these two inequalities

and

Rearrange to get


Now we can combine and to get


So our answer is C




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# 2

The statement "that are less than 4" translates to and the statement "greater than 9" translates to


So together we have


or


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# 3



Start with the given inequality



Distribute


Combine like terms on the left side


Subtract 32 from both sides


Combine like terms on the right side


Divide both sides by -1 to isolate a (note: Remember, dividing both sides by a negative number flips the inequality sign)



Divide

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Answer:
So our answer is


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