SOLUTION: im sorry....it's me again, i think you read my problem wrong, it was #26- 5b+8 divided by 3<3b can you show me how to do that, thank you

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Question 125635This question is from textbook algebra 1
: im sorry....it's me again, i think you read my problem wrong, it was
#26-
5b+8 divided by 3<3b
can you show me how to do that, thank you
This question is from textbook algebra 1

Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
IF YOU MEAN:
(5B+8)/3<3B THEN WE CROSS MULTIPLY.
5B+8<9B
5B-9B<-8
-4B<-8
B>-8/-4 [HERE WE HAVE TO CHANCE THE < SIGN TO A > SIGN BECAUSE WE DIVIDED BY A NEGATIVE NUMBER.
B>2
PROOF
LET B=2.1
(5*2.1+8)/3<3*2.1
(10.5+8)/3<6.3
18.5/3<6.3
6.167<6.3

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