SOLUTION: Can you help me with these 2 problems?
-3x+6 < 12 (the -3x and 6 have are both divided by 2, I couldn't show it because I didn't know how)
and
11y+13 > -1
Algebra.Com
Question 119228: Can you help me with these 2 problems?
-3x+6 < 12 (the -3x and 6 have are both divided by 2, I couldn't show it because I didn't know how)
and
11y+13 > -1
Found 2 solutions by edjones, josmiceli:
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
(-3x+6)/2 < 12
2(-3x+6)/2 < 2*12
-3x+6<24 No fractions
-3x+6-6<24-6
-3x<18
-3x/-3>18/-3 Reverse the sign when dividing or mult. by a neg. numb.
x>-6
.
11y+13>-1
11y+13-13>-1-13
11y>-14
11y/11>-14/11
y>-14/11
.
Ed
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
multiply both sides by 2
subtract 6 from both sides
divide both sides by and change the < to >
answer
-------------------
answer
------------------
You can plug these answers back into the original inequalities
and check them. Say, for the 2nd one, try which
is slightly greater (more positive) than
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