SOLUTION: Suppose x,y,z >0. Prove that {{{x^3 + y^3 >= xyz(x/z + y/z)}}}

SOLUTION: Suppose x,y,z >0. Prove that {{{x^3 + y^3 >= xyz(x/z + y/z)}}}

Algebra.Com

Question 1184377: Suppose x,y,z >0. Prove that
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!



If you prefer, you can reverse the 
steps and omit the "if and only If"'s.

Edwin

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