SOLUTION: Let x, a, b, c be nonnegative real numbers. Prove that (x + cuberoot{abc})^3 <= (x + a)(x + b)(x + c) <= ( x + {(a+b+c)/(3)}^3)

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Question 1179366: Let x, a, b, c be nonnegative real numbers. Prove that
(x + cuberoot{abc})^3 <= (x + a)(x + b)(x + c) <= ( x + {(a+b+c)/(3)}^3)

Answer by math_helper(2461)   (Show Source): You can put this solution on YOUR website!

See this:
https://en.wikipedia.org/wiki/Inequality_of_arithmetic_and_geometric_means
and
https://math.stackexchange.com/questions/1298115/prove-inequality-abbcca-ge-3-abc-1


If you expand the left hand side you will get:
=
Expanding the middle gives:
=
Comparing term-by term, you get two inequalities to prove:


The LHS is a GM, the RHS is an AM, so here the AM-GM inequality applies.
The middle term compared to the RHS (in original problem statement) is then proven in a similar fashion.


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