Hi A 40 liter of 30% ethyl alcohol: How much "x" of a 20% ethyl alcohol should be added to reduce the concentration to 25% ethyl alcohol. .30(40L) + .20x = .25(40+x) .05(40L) = .05x x = 40L of a 20% ethyl alcohol should be added 12 + 8 = (1/4)80 checks Wish You the Best in your Studies.