SOLUTION: A balloon is being inflated. If its radius is increasing at a speed of 2cm/s, determine its surface area as a function of time t. Begin with A(x)=4(pi)x^2. This is the exact qu

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Question 1165072: A balloon is being inflated. If its radius is increasing at a speed of 2cm/s, determine its surface area as a function of time t. Begin with A(x)=4(pi)x^2.
This is the exact question on my assignment and I have no idea how to approach it. I think I am overthinking the question.

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!




But is a function of time, . We are given the rate of change of , namely 2 cm/s.







where the constant of integration, , represents the initial the initial radius, so






John

My calculator said it, I believe it, that settles it


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