SOLUTION: For each point listed below, circle every inequality for which it is a solution. (0,0) (-4, -2) (o, -4) (0,3) (5,0) Answers available; y ≤ 3/2 x +3 2x + y < 10

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Question 1137883: For each point listed below, circle every inequality for which it is a solution.
(0,0)
(-4, -2)
(o, -4)
(0,3)
(5,0)
Answers available;
y ≤ 3/2 x +3
2x + y < 10
y > -1
Answer by Edwin McCravy(20065)   (Show Source): You can put this solution on YOUR website!

(0,0) = (x,y)
y ≤ 3/2 x +3
0 ≤ 3/2(0) +3 
0 ≤ 3 
TRUE

2x + y < 10 
2(0) + 0 < 10
0 < 10 
TRUE

y > -1
0 > -1
TRUE
--------------------
(-4,-2) = (x,y)
 y ≤ 3/2 x +3
-2 ≤ 3/2(-4) +3 
-2 ≤ -6+3
-2 ≤ -3 
FALSE

2x + y < 10 
2(-4) + (-2) < 10
-8 + (-2) < 10
-10 < 10 
TRUE

y > -1
-2 > -1
FALSE
--------------------
(0,-4) = (x,y)
 y ≤ 3/2 x +3
-4 ≤ 3/2(0) +3 
-4 ≤ 0+3
-4 ≤ 3 
TRUE

2x + y < 10 
2(0) + (-4) < 10
0 + (-4) < 10
-4 < 10 
TRUE

y > -1
-4 > -1
FALSE
--------------------
(0,3) = (x,y)
 y ≤ 3/2 x +3
 3 ≤ 3/2(0) +3 
 3 ≤ 0+3
 3 ≤ 3 
TRUE

2x + y < 10 
2(0) + 3 < 10
3 < 10
TRUE

y > -1
3 > -1
TRUE
--------------------
(5,0) = (x,y)
y ≤ 3/2 x +3
0 ≤ 3/2(5) +3 
0 ≤ 15/2 +3
0 ≤ 15/2 +6/2
0 ≤ 21/2  
TRUE

2x + y < 10 
2(5) + 0 < 10
10 < 10 
FALSE

y > -1
0 > -1
TRUE
--------------------
 
Edwin
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