SOLUTION: The height in feet of a projectile with an initial velocity of 96 feet per second and an initial height of 256 feet is a function of time in seconds given by
h(t) = −16t2 +
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Question 1131739: The height in feet of a projectile with an initial velocity of 96 feet per second and an initial height of 256 feet is a function of time in seconds given by
h(t) = −16t2 + 96t + 256.
(a) Find the maximum height of the projectile.___________ft
b) Find the time t when the projectile achieves its maximum height.
t =___________sec
(c) Find the time t when the projectile has a height of 0 feet.
t =_________sec
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
.
If you are a real student, who wants to learn the subject to the level to be able to solve such problems on your own,
then specially for such students I prepared lessons in this site showing and explaining how to do it :
- Problem on an arrow shot vertically upward
- Problem on a ball thrown vertically up from the top of a tower
These lessons are your TEMPLATES.
Read them attentively and then solve your problem on your own.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
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