.
Let x = number of clocks that produced during the regular workweek,
y = number of clocks that produced on overtime.
Then you have these simultaneous equation and inequality
x + y = 10000 (1)
2x + 3y <= 23000 (2)
Multiply eq(1) by (20 (both sides). Keep inequality (2) as is. You will get
2x + 2y = 20000, (3)
2x + 3y <= 23000. (4)
You can transform left part of (4) in this way
2x + 3y = (2x + 2y) + y = 20000 + y, replacing 2x + 2y by 20000 based on (3). Then you get
20000 + y <= 23000, or, equivalently,
y <= 23000 - 20000 = 3000.
Since y <= 3000, then (1) implies x = 10000 - y >= 10000 - 3000 = 7000.
So, your answer is x >= 7000.
Answer. The minimum number of clocks that must be produced during the regular workweek is 7000.
SOLVED.
---------------------
In your condition, every occurrence " comma " can be and must be replaced by "".
In other words, it can be OMITTED, to everybody' satisfaction.