SOLUTION: Please solve for x 7x-2(x+2)-3=4x+5 I keep getting stuck on this problem...the following is what I have 7x-2(x+2)-3=4x+5 7x-2x+2-3=4x+5 7x-2x-1=4x+5 7x-2x+4x=-1+5 Than

Question 111137: Please solve for x
7x-2(x+2)-3=4x+5
I keep getting stuck on this problem...the following is what I have
7x-2(x+2)-3=4x+5
7x-2x+2-3=4x+5
7x-2x-1=4x+5
7x-2x+4x=-1+5
Thank you for your help!!!! :)
Found 2 solutions by solver91311, Earlsdon:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
: Original problem
: Your first error. (distributive property), so you should have
: The next thing I notice is that you are just moving terms back and forth across the equal sign. What you need to do is add or subtract from both sides of the equation to make a zero result on one side and the term, with the opposite sign, appear on the other.
:
. I subtracted 4x from both sides and 1 from both sides.
:
: 7 minus 2 minus 4 is 1, 1 minus 1=0, 4x minus 4x = 0, and 5 minus 1 = 4
:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve for x:
First, simplify the left side of the equation.
Now combine like-terms on the left.
Next, subtract 4x from both sides of the equation.
Finally, add 7 to both sides.

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