SOLUTION: please help me solve this question
it is supposed to be represented in interval notion
x^2<4x+12
I tried moving everything to the left and then factorized and I received (x-6)
Algebra.Com
Question 1093239: please help me solve this question
it is supposed to be represented in interval notion
x^2<4x+12
I tried moving everything to the left and then factorized and I received (x-6) (x+2)<0 and as an answer In interval notion I wrote (-2,6) u (6,infinity)
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39623) (Show Source): You can put this solution on YOUR website!
, which tells you the left side must be LESS THAN 0.
The ROOTS for the expression on left are -2 and +6.
The expression will be LESS THAN 0 for x between -2 and +6, excluding them. (Check that for yourself).
OR
(-2, 6), in interval notation
Answer by greenestamps(13203) (Show Source): You can put this solution on YOUR website!
Your process is fine; but your conclusion is not right....
If you determined the solution set algebraically, then there is something wrong with your work there.
It is easy to see what the solution set should be if you graph the equation corresponding to your inequality.
y = (x-6)(x+2):
On what interval(s) is the function value less than 0?
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