SOLUTION: luke and aisha are 15 miles apart travelling on the same road, in the same direction. Luke is ahead of Aisha driving at a rate of 50 mph, and Aisha is driving at a rate of 55 mph.

Question 1092666: luke and aisha are 15 miles apart travelling on the same road, in the same direction. Luke is ahead of Aisha driving at a rate of 50 mph, and Aisha is driving at a rate of 55 mph. Write and solve an inequality to find when Aisha will be ahead of Luke on the highway. Let x represent time in hours.
Found 2 solutions by jorel1380, ikleyn:
Answer by jorel1380(3719)   (Show Source): You can put this solution on YOUR website!
If x is the time, in hours, then:
x(55)=x(50)+15
5x=15
x=3 hours before Aisha is ahead of Luke
☺☺☺☺

Answer by ikleyn(52817)   (Show Source): You can put this solution on YOUR website!
.
On catching up Travel and Distance problems see the lesson
    - Travel and Distance problems
    - Travel and Distance problems for two bodies moving in the same direction (catching up)
in this site.

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