SOLUTION: how do you do this compound inequality: 10 1/2 < 2z + 18 1/2?
Thank you so much!
Algebra.Com
Question 1063201: how do you do this compound inequality: 10 1/2 < 2z + 18 1/2?
Thank you so much!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
how do you do this compound inequality: 10 1/2 < 2z + 18 1/2?
============
Why do you think it's compound?
---
10 1/2 < 2z + 18 1/2?
Subtract 18 1/2
Divide by 2
RELATED QUESTIONS
How do you solve the inequality 10 1/2 < 2z+18 1/2 (answered by Alan3354)
(x+18)(x-2)(x+11)>0
I need to use at least one inequality or compound inequality to... (answered by jim_thompson5910)
" -2 IS LESS THAN OR EQUAL TO 2x + 1 < 6 "
How do I solve this compound inequality... (answered by stanbon)
Please help with this. How do I add complex numbers?
1. (3+2i)+(4-4i)
2. (1+4i)+... (answered by solver91311)
how do I factor this expression ;
18^2 - 27x + 4
thank you... (answered by josmiceli)
I need help in graphing the following inequality.
I need to do this on the computer and... (answered by rcmcc)
5-2x/3>1/2+x/4. how do i solve this inequality? and what positive intergers will satisfy... (answered by checkley79)
how do you solve and graph this inequality:... (answered by stanbon)
How do you solve for this inequality algebraically.
(x+1)(x-2)(2^x) > 0 (answered by robertb)