SOLUTION: solve exactly over 0 ° &#8804; &#952; < 360° : 4cos^2&#952; - 4sin&#952; =5

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Question 1057643: solve exactly over 0 ° ≤ θ < 360° : 4cos^2θ - 4sinθ =5
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
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solve exactly over 0 ° ≤ θ < 360° : 4cos^2θ - 4sinθ =5
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

 = 5.

Replace  by  to make the equation uniform for . You will get

 = 5,   or

 = 0,   or

 = 0.


Then

 = 0  --->   =   --->   = 210°  OR   = 330°.

Answer.   = 210°  OR   = 330°.


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