SOLUTION: please help me solve these problems:
3/4 (7k - 5)=12
5(3-x)< 3(x-3)
3x + 2 < 5
Algebra.Com
Question 104700: please help me solve these problems:
3/4 (7k - 5)=12
5(3-x)< 3(x-3)
3x + 2 < 5
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
1.
Start with the given equation
Multiply both sides by the LCM of 4. This will eliminate the fractions (note: if you need help with finding the LCM, check out this solver)
Distribute and multiply the LCM to each side
Distribute
Add 15 to both sides
Combine like terms on the right side
Divide both sides by 21 to isolate k
Divide
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Answer:
So our answer is
2.
Start with the given inequality
Distribute
Subtract 15 from both sides
Subtract 3x from both sides
Combine like terms on the left side
Combine like terms on the right side
Divide both sides by -8 to isolate x (note: Remember, dividing both sides by a negative number flips the inequality sign)
Divide
--------------------------------------------------------------
Answer:
So our answer is
Start with the given inequality
Subtract 2 from both sides
Combine like terms on the right side
Divide both sides by 3 to isolate x
Divide
--------------------------------------------------------------
Answer:
So our answer is
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