SOLUTION: Solve the inequality and express the solution in terms of intervals whenever possible. (I forgot how to get common denominator) (1/x-2) >= (3/x+1) (1/x-2) � (3/x+1) >=0

Question 1045845: Solve the inequality and express the solution in terms of intervals whenever possible. (I forgot how to get common denominator)
(1/x-2) >= (3/x+1)
(1/x-2) � (3/x+1) >=0
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!

<===> .
===> The critical values of this inequality are -1, 2, and 7/2.
The expression is
--non-negative over (, -1);
--negative over (-1,2);
--non-negative over (2,7/2];
--negative over (7/2, ).
Therefore the solution set is (, -1)∪(2,7/2].
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