SOLUTION: Prove that for n<0<n
a. |m/n|=|m|/|n|
b. |mn|=|m||n|
c. -|m|<=m<=|m|
Algebra.Com
Question 1042516: Prove that for n<0
a. |m/n|=|m|/|n|
b. |mn|=|m||n|
c. -|m|<=m<=|m|
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
I will prove only (a). You do the rest....
if x > 0; if x < 0. (And of course, .)
Given: n < 0.
Case I. m > 0.
===> , and so
Case II. m < 0.
===> , and so .
Case III. m = 0 is trivial after substitution of 0 for m to both sides of the equation.
Hope you get the drift...
RELATED QUESTIONS
Solve the equation a = m - n for the variable n.
A. n = a + m
B. n = m - a
C. (answered by dkppathak)
If m and n are consecutive even integers and m > n > 0, how many integers are greater... (answered by Fombitz)
solve for y y/m + y/n = p
a. y=mn/p
b. y=mnp/m+n
c.... (answered by edjones)
(a^m+n)^m-n (answered by Fombitz)
m-n/n-m
(answered by jim_thompson5910,mananth)
(m-n)-(m+n) (answered by Alan3354)
If {{{a^m*a^n=a^mn}}},then m(n-2)+n(m-2)is?options are (a)-1,(b)1 (c)0... (answered by jim_thompson5910)
Solve for n:
R=M(1+n)
What I have done:
R=M*1+M*n
R=M+Mn
R-M=M-M+Mn
R-M=Mn... (answered by Fombitz)
indicated letter
n=m+c, for... (answered by checkley77)