SOLUTION: I need to solve this problem please help. Graph inequalities 3x+y≤1 3(0)+0≤1 X=1 this is my answer is this correct?

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Question 103638: I need to solve this problem please help. Graph inequalities
3x+y≤1
3(0)+0≤1
X=1 this is my answer is this correct?
Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!
1. Solve the equation for y (if necessary).
=> or

2. Graph the equation as if it contained an = sign.
3. Draw the line solid if the inequality is or
4. Draw the line dashed if the inequality is < or >
5. Pick a point not on the line to use as a test point.
The point (0,0) is a good test point if it is not on
the line.
6. If the point makes the inequality true, shade that
side of the line. If the point does not make the
inequality true, shade the opposite side of the line.

now you can graf it and shade everything to the right from the line.


Solved by pluggable solver: Graphing Linear Equations
In order to graph we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=-2



Multiply

Add

So here's one point (-2,-7)




Now lets find another point

Plug in x=-1



Multiply

Add

So here's another point (-1,-4). Add this to our graph





Now draw a line through these points

So this is the graph of through the points (-2,-7) and (-1,-4)


So from the graph we can see that the slope is (which tells us that in order to go from point to point we have to start at one point and go up 3 units and to the right 1 units to get to the next point) the y-intercept is (0,)and the x-intercept is (,0) ,or (,0)


We could graph this equation another way. Since this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,).


So we have one point (0,)





Now since the slope is , this means that in order to go from point to point we can use the slope to do so. So starting at (0,), we can go up 3 units



and to the right 1 units to get to our next point


Now draw a line through those points to graph


So this is the graph of through the points (0,-1) and (1,2)
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