SOLUTION: Prove that 0,3 < S < 0,4 S= 1/(1*4) + 1/(4*7) + 1/(7*10) + ... + 1/(2014*2017)

Algebra.Com
Question 1023304: Prove that 0,3 < S < 0,4
S= 1/(1*4) + 1/(4*7) + 1/(7*10) + ... + 1/(2014*2017)

Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!
S = +...+
=*(+...+ )
= = S
But = 0.333168... >0.3, and also
....< 0.4
Hence,
0.3 < S < 0.4.

RELATED QUESTIONS

7-4+(3*0)+1= (answered by stanbon)
Solve: s-4√s-1=0 (answered by solver91311)
1/3 s + 7/9 = 4/3... (answered by checkley77)
1/3 s + 7/9 = 4/3... (answered by JBarnum)
1/3 s+7/9=4/3... (answered by Fombitz)
Multiply (s+1/3)(s+1/4) (answered by Fombitz)
(s+1/3)(s+1/4) (answered by rfer)
7-4+3 multiple by... (answered by Timnewman)
Prove the argument: 1. p -> q 2. r \/ s 3. ~s -> ~t 4. ~q \/ s 5. ~s 6. (~p... (answered by Edwin McCravy)