SOLUTION: Use the position function \qquad s(t) = -16t^2 + v0t + s_0 \qquad v_0 = {initial velocity}, s_0 ={initial position}, t ={time} to answer the following question.

Question 1018970: Use the position function
\qquad s(t) = -16t^2 + v0t + s_0
\qquad v_0 = {initial velocity},
s_0 ={initial position}, t ={time}
to answer the following question.
You throw a ball straight up from a rooftop 122 feet high with an initial velocity of 96 feet per second. During which time period will the ball's height exceed that of the rooftop?
ANSWER: Between
and
seconds.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
You throw a ball straight up from a rooftop 122 feet high with an initial velocity of 96 feet per second. During which time period will the ball's height exceed that of the rooftop?
-------------
h(t) = -16t^2 + 96t + 122
Find t for h(t) = 122
---
-16t^2 + 96t + 122 = 122
-16t^2 + 96t = 0
t = 0, t = 6
--> 0 < t < 6

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