SOLUTION: In 18x^3 + 24x^2 + 8x >= 0 (solved in interval notation), why is [-2/3] on it's own with the correct answer being [-2/3]U[0,infinity)? Rather than (-infinity,-2/3]U[0,infinity)?

SOLUTION: In 18x^3 + 24x^2 + 8x >= 0 (solved in interval notation), why is [-2/3] on it's own with the correct answer being [-2/3]U[0,infinity)? Rather than (-infinity,-2/3]U[0,infinity)?

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Question 1010053: In 18x^3 + 24x^2 + 8x >= 0 (solved in interval notation), why is [-2/3] on it's own with the correct answer being [-2/3]U[0,infinity)? Rather than (-infinity,-2/3]U[0,infinity)?
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

as you can see must be >=
so, for that reason you cannot use interval (,]U[,)
solutions are: and
and interval solution is:
[]U[,)
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