SOLUTION: The sum of two integers is 64. One integer is 20 less than twice the other.
Find the smaller integer.
Algebra.Com
Question 1009321: The sum of two integers is 64. One integer is 20 less than twice the other.
Find the smaller integer.
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the integers x and y. Then we have
x + y = 64 and
x = 2y - 20
Substitute the second into the first equation and get
2y - 20 + y = 64
3y - 20 = 64
3y = 84
y = 28
x = 36
The smaller is 28.
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