That is what you wrote. If you want something different, then it needs to be written differently.
You want this?
Do you know why and how?
, ID and use LCD
The critical x-values are at -4, -1, +3.
Test the x-axis intervals by picking any convenient value in each interval.
The intervals to check are (-infininty,-4), (-4, -1), (-1, 3), (3, infinity).
INTERVAL PICK VAL SIGNS RESULT SIGN
(-infininty,-4) -5 (-)(-)(-)/(-) (+)
(-4, -1) -2 (-)(-)(+)/(-) (-)
(-1, 3) 0 (-)(-)(+)/(+) (+)
(3, infinity) 4 (-)(+)(+)/(+) (-)
The left member in the inequality is supposed to be greater than 0, which means POSITIVE in value. The interval analysis shows for which domain will satisfy the inequality, according to the resulting signs.
Solution SET is the intervals AND ; those are the x values which satisfy the inequality.