SOLUTION: square root of 5 more than twice a number is 7
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Question 994111: square root of 5 more than twice a number is 7
Found 2 solutions by Theo, MathTherapy:
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
7 = 2x + sqrt(5)
subtract 2x from both sides of the equation to get:
7 - 2x = sqrt(5)
square both sides of the equation to get:
(7-2x)^2 = 5
simplify the left side of the equation by squaring it to get:
49 - 28x + 4x^2 = 5
subtract 5 from both sides of the equation to get:
49 - 5 - 28x + 4x^2 = 0
combine like terms to get:
44 - 28x + 4x^2 = 0
rearrange the terms in descending order to get:
4x^2 - 28x + 44 = 0
factor out the gcf to get:
4 * (x^2 - 7x + 11) = 0
divide both sides of the equation by 4 to get:
x^2 - 7x + 11 = 0
factor the quadratic using the quadratic formula to get:
x = 4.618 and x = 2.382
answers are rounded to the third decimal place.
here's some info on the quadratic formula.
http://www.regentsprep.org/regents/math/algtrig/ate3/quadformula.htm
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
square root of 5 more than twice a number is 7
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