SOLUTION: Jim built a rectangular shed with a total floor surface area will be 126 sq.ft if the lenght is 4 feet more than twice it's width what is the width of the dog house. Please help me

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Question 941480: Jim built a rectangular shed with a total floor surface area will be 126 sq.ft if the lenght is 4 feet more than twice it's width what is the width of the dog house. Please help me with this
Found 2 solutions by srinivas.g, MathTherapy:
Answer by srinivas.g(540)   (Show Source): You can put this solution on YOUR website!
surface area of rectangular floor = 126 sq fr
let x be the width
length = 2x+4
area = length * width
126 =(2x+4)*x

move 126 to the right

Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=1024 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 7, -9. Here's your graph:


x= 7 or -9
but x represents width. it cannot be negative
hence x= 7
width (x) = 7 feet
Answer by MathTherapy(10553)   (Show Source): You can put this solution on YOUR website!
Jim built a rectangular shed with a total floor surface area will be 126 sq.ft if the lenght is 4 feet more than twice it's width what is the width of the dog house. Please help me with this 


Let width be W

Then length = 2W + 4

Since area is 126 sq feet, we get: W(2W + 4) = 126







(W - 7)(W + 9) = 0

W, or width =  ft             OR            W = - 9 (ignore) 

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