SOLUTION: Doreen Schmidt is a chemist. She needs to prepare 32 ounces of a 11% hydrochloric acid solution. Find the amount of 16% solution and the amount of 8% solution she should mix to get

Question 924076: Doreen Schmidt is a chemist. She needs to prepare 32 ounces of a 11% hydrochloric acid solution. Find the amount of 16% solution and the amount of 8% solution she should mix to get this solution.
How many ounces of the 16% acid solution should be in the mixture?
Found 2 solutions by TimothyLamb, MathTherapy:
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = ounces of 16%
y = ounces of 8%
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11*32 = 16x + 8y
x + y = 32
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put the system of linear equations into standard form
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16x + 8y = 11*32
x + y = 32
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16x + 8y = 352
x + y = 32
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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answer:
x = ounces of 16% = 12
y = ounces of 8% = 20
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Solve systems of linear equations up to 6-equations 6-variables:
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Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Doreen Schmidt is a chemist. She needs to prepare 32 ounces of a 11% hydrochloric acid solution. Find the amount of 16% solution and the amount of 8% solution she should mix to get this solution.
How many ounces of the 16% acid solution should be in the mixture?

Let amount of 16% solution to mix, be S
Then amount of 8% solution to mix is: 32 - S
Therefore, we have: .16S + .08(32 - S) = .11(32)
.16S + 2.56 - .08S = 3.52
.16S - .08S = 3.52 - 2.56
.08S = .96
S, or amount of 16% solution to mix = , or oz
Amount of 8% solution to mix = 32 - 12, or oz
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