SOLUTION: " 8 pints of a 20% solution of alcohol in water are mixed with 2 pints of a 40% solution of alcohol in water. What is the percentage of alcohol in the new solution? "
I can't f
Algebra.Com
Question 922842: " 8 pints of a 20% solution of alcohol in water are mixed with 2 pints of a 40% solution of alcohol in water. What is the percentage of alcohol in the new solution? "
I can't figure out the formula.
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let x=percentage of alcohol in new solution
Now we know that the AMOUNT of pure alcohol that exists before the mixture takes place(0.20*8+0.40*2) has to equal the AMOUNT of pure alcohol that exists after the mixture takes place(x*10). Sooo our equation to solve is:
0.20*8+0.40*2=10x
1.6+0.8=10x
10x=2.4
x=0.24 or 24%
CK
0.20*8+0.40*2=0.24*10
1.6+0.8=2.4
2.4=2.4
Hope this helps---ptaylor
RELATED QUESTIONS
Suppose 8 pints of a 13% alcohol solution is mixed with 2 pints of a 60% alcohol... (answered by checkley79,richwmiller)
Suppose 44 pints of aa 13% alcohol solution is mixed with 66 pints of aa... (answered by ankor@dixie-net.com)
how many pints of a 11% alcohol solution should jenny mix with 15 pints of a 5% alcohol... (answered by josmiceli)
We have a 20% alcohol solution and 50% alcohol solution. How many pints must be used from (answered by mananth)
six liters of a 30% solution of alcohol in water is mixed with 4 liters of a 50% solution (answered by LinnW)
how much alcohol in pints must be added to 80 pints of a solution of alcohol and iodine... (answered by nerdybill)
A solution contains 11 pints of antifreeze and 8 pints of water. How many pints of water... (answered by josmiceli)
one liter of water is added to 5 liters of a 20% solution of alcohol in water. what is... (answered by josgarithmetic)
We have 20% alcohol solution and a 50% solution. How many pints must be used from each to (answered by checkley77)