SOLUTION: the formula h=-16t^2 48t 160 given the height of an object thrown from a building 160 feet high with an initial speed of 48 ft/sec where t is measured in seconds find the time for
Algebra.Com
Question 811249: the formula h=-16t^2 48t 160 given the height of an object thrown from a building 160 feet high with an initial speed of 48 ft/sec where t is measured in seconds find the time for the object to hit the ground and find the maximum height of the object
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
h=-16t^2 48t 160 'should be
h=-16t^2+48t+ 160 if it was thrown upwards
h = 196, t = 3/2
it hits the ground at t = 5
maximum height makes no sense if it was thrown downwards
RELATED QUESTIONS
An object is thrown upward from the top of a 160-foot building with an initial velocity... (answered by Alan3354)
Hello I really need some assistance with the following algebra word problem:
"An... (answered by josmiceli)
An object is thrown upward from the top of a 160 foot building with an initial velocity... (answered by mananth)
Please help me! I think that the answer is 5 seconds, but I don't know. Please show... (answered by Alan3354)
height of an object thrown from 60 feet up, with an initial speed of 48 feet/second is... (answered by htmentor,josmiceli)
An object is thrown upward from the top of a 160-foot building with an initial... (answered by ankor@dixie-net.com)
an object is thrown upward from the top of a 64 foot building with an initial velocity of (answered by ikleyn)
Applications of Quadratic Equations​ (Modeling):
1.If you throw a ball straight up... (answered by Alan3354)
If you throw a ball straight up from a rooftop 160 feet high with an initial speed of 48 (answered by greenestamps)