SOLUTION: Given two consecutive integers. The sum of two times the first integer and four times the second integer is 82. Find the integers.

SOLUTION: Given two consecutive integers. The sum of two times the first integer and four times the second integer is 82. Find the integers.

Algebra.Com

Question 749434:
Given two consecutive integers. The sum of two times the first integer and four times the second integer is 82. Find the integers.
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
LET X & (X+1) BE THE 2 INTEGERS.
2X+4(X+1)=82
2X+4X+4=82
6X=82-4
6X=78
X=78/6
X=13 ANS.
13+1=14 ANS.
PROOF:
2*13+4(14)=82
26+56=82
82=82
RELATED QUESTIONS
Given two consecutive integers. The sum of four times the first integer and five times... (answered by josgarithmetic,ikleyn)

1,The average of three consecutive integers is 8.find the integers. (answered by josgarithmetic)

given two consecutive integers. the sum of two times the first integer and three times... (answered by ikdeep)

the sum of four consecutive even integers is two more than 5 times the first integer.... (answered by Edwin McCravy)

Given two consecutive integers. The sum of 3 times the 1st integer and four times the 2nd (answered by jim_thompson5910)

find the sum of three consecutive even integers such that four times first and three... (answered by CubeyThePenguin)

Find three consecutive even integers such that four times the third integer is four more... (answered by ankor@dixie-net.com)

The sum of an even integer and two times the next consecutive even integer is 82. find... (answered by Alan3354)

Find three consecutive odd integers such that the sum of the first integer, twice the... (answered by ewatrrr)