SOLUTION: Find the vertex axis of symmetry (XS) max or min function value X-intercepts Y intercept and graph the function: F(x)= -x^2 - 2x + 7
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Question 689120: Find the vertex axis of symmetry (XS) max or min function value X-intercepts Y intercept and graph the function: F(x)= -x^2 - 2x + 7
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the vertex axis of symmetry (XS) max or min function value X-intercepts Y intercept and graph the function: F(x)= -x^2 - 2x + 7
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The vertex occurs at x = -b/(2a) = 2/(2*-1) = -1
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F(-1) = -1+2+7 = 8
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Vertex at (-1,8)
Max at (-1,8)
===========================
Axis of symmetry: x = -1
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y-intercept: f(0) = 7
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x-intercept = ?
Solve -x^2-2x+7 = 0
x = [2+- sqrt(4-4*-1*7)]/(-2)
x = [2+- sqrt(32)]/(-2)
x = [2 +- 4sqrt(2)]/(-2)
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x-intercepts: x = -1+2sqrt(2) or x = -1-2sqrt(2)
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Cheers,
Stan H.
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