SOLUTION: Solution A is 12% acid and Solution B is 4% acid. If a technician wants to mix them to make 60 liters of Solutin C which is 10% acid, how many liters of each should be mixed togeth

Question 6203: Solution A is 12% acid and Solution B is 4% acid. If a technician wants to mix them to make 60 liters of Solutin C which is 10% acid, how many liters of each should be mixed together?
Answer by roy_algebra2006(2) (Show Source): You can put this solution on YOUR website!
Let us assume that solution A required is 'x' litres & solution B required is 'y' litres.
we can see that x+y=60---------(1)
now 10% acid =10*60/100 litres=6 litres.
now the tricky part....
12% 0f 'x' =12*x/100 & 4% of 'y'=4*y/100 ......(all in litres)
thus we get 12*x/100+4*y/100=6
=>3*x/25+y/25=6
=>3*x+y=150--------(2)
solving the above simultaneous equations numbered (1)& (2)......
we get
x=45 & y=15
hence solution A required is 45 litres & solution B required is 15 litres.
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