SOLUTION: Can someone help me to translate the following: Find three consecutive odd integers such that 3 times the second minus the third is 11 more than the first?

Algebra ->  Algebra  -> Human-and-algebraic-language -> SOLUTION: Can someone help me to translate the following: Find three consecutive odd integers such that 3 times the second minus the third is 11 more than the first?      Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 619071: Can someone help me to translate the following:
Find three consecutive odd integers such that 3 times the second minus the third is 11 more than the first?
Answer by ewatrrr(10682) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Find three consecutive odd integershighlight%28x%29, highlight%28x%2B2%29, highlight%28x%2B4%29

such that 3 times the second minus the third is 11 more than the first?

 3(x+2) - (x+4) = x+11

 3x + 6 -x-4 = x + 11

    2x + 2 = x + 11

     x = 9 

  9, 11 , 13

CHECKING our Answer***

3·11 - 13 = 20