SOLUTION: Help Please! Find the exact an approximate solution. Find two positive real numbers that differ by one and have a product of one.

Question 60580: Help Please! Find the exact an approximate solution. Find two positive real numbers that differ by one and have a product of one.
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
Help Please! Find the exact an approximate solution. Find two positive real numbers that differ by one and have a product of one.
LET ONE NUMBER = X
OTHER NUMBER = X-1
PRODUCT = X(X-1)=1
X^2-X=1
X^2-X-1=0.....COMPARING WITH AX^2+BX+C=0...A=1...B=-1....C=-1

SINCE POSITIVE NUMBERS ARE ASKED FOR THEY ARE
[1+SQRT(5)]/2 AND [1+SQRT(5)]/2 -1..OR ....[SQRT(5)-1]/2
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